Case Study : Acme Water Pumps
The Acme Water Pump company has a problem. The pumps are fairly expensive to make and store, so the company tends to keep the inventory low. At the same time, it is important to respond to demands quickly, since a customer who wants a water pump is very likely to get one from a competitor if Acme doesn’t have one available immediately. A cm e’s current policy to produce pumps is to produce 100 per week, which is the average demand. Even this is a problem, as the production manager has pointed out, since the equipment is also used for other products and the lot size of 300 would be much more efficient. He said he is currently set up for water pump production for the next week and states that he has capacity available to produce 300 at a time next week.
The following lists the forecasts and actual customer orders for the next 12 weeks
The president of Acme has said that he wants to consider using a formal MPS with ATP logic to try to meet demand more effectively without a large impact on inventory. Acme has decided to use a demand time fence at the end of week 3 and has also found out that its current inventory is 25 units. Assume Acme will use the MPS lot size of 300 and that it will produce the first of those lots in week 1.
Assignment
-
- Develop a master schedule using the information above.
- A customer has just requested a major order of 45 pumps for delivery in week 5. What would you tell the customer about having such an order? Why? What, if any thing, would such an order do to the operation?
Answer
-
- Keep inventory low
-
- Respond demand quickly
-
- currently produce 100 pumps a week.
-
- Setting up 300 pumps a week
-
- Current inventory is 25 units.
- Use MPS lot size of 300 (first week)
1. Master schedule
Current inventory is 25 units.
No | Period | A | B | C | D | E | F | G | H | I | J | K | L |
1 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | |
2 | Forecast | 90 | 120 | 110 | 80 | 85 | 95 | 100 | 110 | 90 | 90 | 100 | 110 |
3 | Cust. orders | 105 | 97 | 93 | 72 | 98 | 72 | 53 | 21 | 17 | 6 | 2 | 5 |
4 | Projected Available Balance | 220 | 123 | 30 | 250 | 152 | 57 | 257 | 147 | 57 | 267 | 167 | 57 |
5 | MPS | 300 | 300 | 300 | 300 | ||||||||
6 | ATP | 30 | 58 | 209 | 287 |
Link excel :
https://docs.google.com/spreadsheets/d/1m0ktebzDEZQYW-7Nhn-eBD0oF7fnwUZoC4A38jNx16w/edit#gid=0
Formula Projected Available Balance :
A4 = A5+25-A3 = 300 + 25 – 105 = 220
B4 = A4-B3 = 220 – 97 = 123
C4 = B4-C3 = 123 – 93= 30
D4 = D5+C4-MAX(D23) = 300 + 30 – MAX(80:73) = 250
E4 = D4-MAX(E2:E3) = 250 – MAX(85:98) = 152
F4 = E4-MAX(F2:F3) = 152 – MAX(95:72) = 57
G4 = G5+F4-MAX(G2:G3) = 300 + 57 – MAX(100:53) = 257
H4 = G4-MAX(H2:H3) = 257 – MAX(110:21) = 147
I4 = H4-MAX(I2:I3) = 147 – MAX(90:17) = 57
J4 = J5+I4-MAX(J2:J3) = 300 + 57 – MAX(90:6) = 267
K4 = J5-MAX(K2:K3) = 267 – MAX(100:2) = 167
L4 = K4-MAX(L2:L3) = 167 – MAX(110:5) = 57
Formula ATP:
A6 =A5+25-SUM(A3:C3) = 300 + 25 – SUM(A3:C3) = 30
D6 = D5-SUM(D3:F3) = 300 – SUM(D3:F3) = 58
G6 = G6-SUM(G3:I3) = 300 – SUM(G3:I3) = 209
J6 = J6-SUM(J3:L3) = 300 – SUM(J3:L3) = 287
2. Request of 45 pumps
Cust. orders week 5 = 98 + 45 = 143
Period | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 |
Forecast | 90 | 120 | 110 | 80 | 85 | 95 | 100 | 110 | 90 | 90 | 100 | 110 | |
Cust. orders | 105 | 97 | 93 | 72 | 143 | 72 | 53 | 21 | 17 | 6 | 2 | 5 | |
PAB | 25 | 220 | 123 | 30 | 250 | 107 | 12 | 212 | 102 | 12 | 222 | 122 | 12 |
ATP | 30 | 0 | 0 | 13 | 0 | 0 | 209 | 0 | 0 | 287 | 0 | 0 | |
MPS | 300 | 0 | 0 | 300 | 0 | 0 | 300 | 0 | 0 | 300 | 0 | 0 |
Link excel : https://docs.google.com/spreadsheets/d/1m0ktebzDEZQYW-7Nhn-eBD0oF7fnwUZoC4A38jNx16w/edit#gid=1987357231
Berdasarkan penghitungan di atas, tambahan permintaan 45 pump pada minggu ke 5 tidak berdampak pada kekurangan persediaan pada minggu-minggu berikutnya. Sehingga, tidak perlu adanya penggunaan produk yang dialokasikan dari ATP pada minggu sebelumnya. Permintaan tersebut dapat diterima tanpa perlu ada penambahan proses operasi pada produksi.
Dilihat sebanyak : 1055 kali
Leave a Reply